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0=3t^2-9t-7
We move all terms to the left:
0-(3t^2-9t-7)=0
We add all the numbers together, and all the variables
-(3t^2-9t-7)=0
We get rid of parentheses
-3t^2+9t+7=0
a = -3; b = 9; c = +7;
Δ = b2-4ac
Δ = 92-4·(-3)·7
Δ = 165
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{165}}{2*-3}=\frac{-9-\sqrt{165}}{-6} $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{165}}{2*-3}=\frac{-9+\sqrt{165}}{-6} $
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